The average rate of change of h(t) between t = 2 and t = 5 is -112. See the explanation below.
What does this average rate of change means in terms of the context?
Because the average rate of change is negative it simply means that the slope of the Quadratic function is also negative.
What is the calculation showing the above answer in part A?
We are given the following:
When t =2; h(2) = 336
When t = 5; h(5) = 0
Recall that the Average Rate of Change on the interval [a,b] is given as:
[ta - tb]/(b-a)
Since the state interval is [2,5]; and
h(2) = 336; and
h(5) = 0
Hence
ARC = 0-336/5-2
= -336/3
= -112
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