Answer:
1/3(9x+12)+4x+6=x
We move all terms to the left:
1/3(9x+12)+4x+6-(x)=0
Domain of the equation: 3(9x+12)!=0
x∈R
We add all the numbers together, and all the variables
3x+1/3(9x+12)+6=0
We multiply all the terms by the denominator
3x*3(9x+12)+6*3(9x+12)+1=0
Wy multiply elements
9x^2(9+18x(9+1=0
Step-by-step explanation:
