Answer:
The equation in Point-slope form of a line that has a slope of 3/4 and passes through the point (-4, -12) is:
[tex]y+12=\frac{3}{4}\left(x+4\right)[/tex]
The graph of the equation line is also attached below.
Step-by-step explanation:
Given
To determine
We have to determine the equation in Point-Slope Form.
We know that the Point-slope form of a line equation is defined as
[tex]y-y_1=m\left(x-x_1\right)[/tex]
where
- [tex]m[/tex] is the slope of the line
- [tex]\left(x_1,\:\:y_1\right)[/tex] is the point
In our case:
substituting the values m = 3/4 and the point (x₁, y₁) = (-4, -12) in the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-\left(-12\right)=\frac{3}{4}\left(x-\left(-4\right)\right)[/tex]
Apply rule: [tex]-\left(-a\right)=a[/tex]
[tex]y+12=\frac{3}{4}\left(x+4\right)[/tex]
Therefore, the equation in Point-slope form of a line that has a slope of 3/4 and passes through the point (-4, -12) is:
[tex]y+12=\frac{3}{4}\left(x+4\right)[/tex]
The graph of the equation line is also attached below.
