a. The surface area of the smaller ganza is [tex]296.73cm^{2}[/tex]
The surface area of the larger ganza is [tex]1036.2cm^{2}[/tex]
b. The weight of the larger ganza is [tex]3.84[/tex] pounds.
Surface area :
From given figure,
Radius of smaller ganza ,[tex]r_{1}=3.5/21.75cm[/tex]
height of smaller ganza, [tex]h_{1}=10cm[/tex]
a. The surface area of the smaller ganza is,
[tex]S_{1}= 2 \pi r^{2} + 2\pi rh[/tex]
[tex]S_{1}=2 * 3.14 * 3.5 * 3.5 + 2 * 3.14 * 3.5* 10\\\\S_{1}=76.93+ 219.8\\\\S_{1}=296.73cm^{2}[/tex]
The surface area of the larger ganza
[tex]S_{2}= 2\pi r^{2} + 2\pi rh[/tex]
[tex]S_{2}= 2 * 3.14 * 5.5 * 5.5 + 2 * 3.14 * 5.5* 24.5\\\\S_{2}= 189.97+846.23\\\\S_{2} = 1036.2 cm^{2}[/tex]
b. Since, the surface area is proportional to the weight.
and The weight of the smaller ganza is 1.1 pounds.
[tex]\frac{1.1}{w}=\frac{296.73}{1036.2}\\ \\ w=\frac{1036.2*1.1}{296.73}\\ \\w=3.84[/tex]
Learn more about the surface area here:
https://brainly.com/question/16997207
