Answer:
[tex]T=-75.59\°C[/tex]
Explanation:
Hello!
In this case, since we can treat neon as an ideal gas, it is possible for us to use the following equation:
[tex]PV=nRT[/tex]
Whereas the temperature is out unknown, so we proceed as follows:
[tex]T=\frac{PV}{nR}[/tex]
However, we need the moles of neon in 0.02 kg as shown below:
[tex]n=0.02kg*\frac{1000g}{1kg}*\frac{1mol}{20.17g} =0.992mol[/tex]
Thus, we obtain the following temperature in Kelvins:
[tex]T=\frac{6.43atm*2.5L}{0.992mol*0.08206\frac{atm*L}{mol*K}} \\\\T=197.56K[/tex]
Therefore, in degree Celsius it is:
[tex]T=197.56-273.15\\\\T=-75.59\°C[/tex]
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