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A chip is burned beneath an aluminum container holding 28.7 g of water causing the temperature of the water to increase from 11.3 °C to 33.2 °C. How many joules of heat were absorbed by the water? Water’s specific heat is 4.18 J/gºC

Respuesta :

Answer:

Q = 2627.25 J

Explanation:

Given that,

The mass of water, m = 28.7 g

The temperature of the water to increase from 11.3 °C to 33.2 °C

The specific heat of water is 4.18 J/gºC

The heat absorbed by the water is given by :

[tex]Q=mc\Delta T\\\\Q=28.7 \times 4.18 \times (33.2-11.3)\\\\Q=2627.25\ J[/tex]

So, 2627.25 J of heat is absorbed by the water.

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