Given:
[tex]\dfrac{1}{4}\text{ to }\dfrac{1}{2}[/tex]
To find:
The percent of change, round to the nearest 10th of a percent.
Solution:
We have,
Initial value = [tex]\dfrac{1}{4}[/tex]
New value = [tex]\dfrac{1}{2}[/tex]
We know that, the percentage change is
[tex]\%\text{ change}=\dfrac{\text{New value - Initial value}}{\text{Initial value}}\times 100[/tex]
Putting the given values, we get
[tex]\%\text{ change}=\dfrac{\dfrac{1}{2}-\dfrac{1}{4}}{\dfrac{1}{4}}\times 100[/tex]
[tex]\%\text{ change}=\dfrac{\dfrac{2-1}{4}}{\dfrac{1}{4}}\times 100[/tex]
[tex]\%\text{ change}=\dfrac{\dfrac{1}{4}}{\dfrac{1}{4}}\times 100[/tex]
[tex]\%\text{ change}=1\times 100[/tex]
[tex]\%\text{ change}=100\%[/tex]
Here, the % change is positive, it represents the percent increase.
Therefore, the percent of change is 100% of increase.
