Suppose one Sherpa uses a force of 980 N to move a load of equipment to a height of 20 meters in 25 seconds. How much power is used?

Respuesta :

F = 980 N

h = 20 m

t = 25 s

P=? (power)

W=F*h   (work)

P=W*t  

P=F*h*t

P=980*20*25 =490000 W = 490 kW = 0.49 MW