Answer:
The equation of the line that passes through the point (-2, 0) and has a slope -2 is:
The graph of the line equation [tex]y = -2x - 4[/tex] is also attached.
Step-by-step explanation:
The slope-intercept form of the line equation
[tex]y = mx+b[/tex]
where
Given that the equation of the line that passes through the point (-2, 0) and has a slope of -2.
so we have
The first step we need to do is to determine the y-intercept of the line.
so substituting m = -2 and (-2, 0) in the slope-intercept form of the line equation to determine the y-intercept b
[tex]y = mx + b[/tex]
[tex]0 = -2(-2) + b[/tex] ∵ (x, y) = (-2, 0)
[tex]0 = 4 + b[/tex]
[tex]b = -4[/tex]
Thus, the y-intercept b of the line is: b = -4
The second step is to substitute b = -4 and m = -2 in the slope-intercept form of the line equation
[tex]y = mx + b[/tex]
[tex]y = -2x + (-4)[/tex]
[tex]y = -2x - 4[/tex]
Therefore, the equation of the line that passes through the point (-2, 0) and has a slope -2 is:
The graph of the line equation [tex]y = -2x - 4[/tex] is also attached.
