Lead will react with hydrochloric acid to produce lead (II) chloride and hydrogen. How many moles of hydrochloric acid are needed to completely react with 0.36 mol of lead?

Respuesta :

Answer:

0.72 moles of hydrochloric acid are needed to completely react with 0.36 mol of lead.

Explanation:

The balanced  reaction is:

Pb + 2 HCl → PbCl₂ + H₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagent participate:

  • Pb: 1 mole
  • HCl: 2 moles

You can apply the following rule of three: if by stoichiometry of the reaction 1 mole of Pb reacts with 2 moles of HCl, 0.36 moles of Pb will react with how many moles of HCl?

[tex]amount of moles of HCl=\frac{0.36 molesof PB*2 moles of HCl}{1 mole of Pb}[/tex]

amount of moles of HCl= 0.72 moles

0.72 moles of hydrochloric acid are needed to completely react with 0.36 mol of lead.

The moles of HCl needed to completely react with 0.36 mole of lead is 0.72 moles.

What is stoichiometry of reaction?

Stoichiometry of the reaction tells about the relative amount of the reactants and products present in that reaction in terms of coefficient.

Given chemical reaction is:

Pb + 2HCl → PbCl₂ + H₂

From the stoichiometry of the reaction, it is clear that:
1 mole of Pb = react with 2 moles of HCl

0.36 mole of Pb = react with 2×0.36 = 0.72 moles of HCl

Hence, the required moles of HCl is 0.72 moles.

To know more about stoichiometry, visit the below link:

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