contestada

i) Coordinates of point P

a) (1,1) b) (1,2) c) (2,1) d) (1,0)

ii) Coordinates of point Q

a) (0,-3) b) (-3,0) c) (-3,-3) d) (0,3)

iii) Coordinates of point T

a) (-4,-2) b) (-2,-4) c) (4,-2) d) (-2,4)

iv) (Ordinate of T) – (Abscissa of R)

a) -4 b) 4 c) 0 d) -2

v) (Abscissa of Q) – (Ordinate of S)

a) -4 b) 4 c) 2 d) -2

i Coordinates of point Pa 11 b 12 c 21 d 10ii Coordinates of point Qa 03 b 30 c 33 d 03iii Coordinates of point Ta 42 b 24 c 42 d 24iv Ordinate of T Abscissa of class=

Respuesta :

Given:

Five points P, Q, R, S ,T on a coordinate plane.

To find:

The coordinates of (i) P, (ii) Q, (iii) T, (iv) (Ordinate of T) – (Abscissa of R) and (v) (Abscissa of Q) – (Ordinate of S).

Solution:

From the given graph it is clear that the coordinates of given points are

P = (1,1)

Q = (-3,0)

R = (-2,-3)

S = (2,1)

T = (4,-2)

(i)

Coordinates of point P are (1,1).

Therefore, the correct option is (a).

(ii)

Coordinates of point Q are (-3,0).

Therefore, the correct option is (b).

(iii)

Coordinates of point T are (4,-2).

Therefore, the correct option is (c).

(iv)

Ordinate is y-coordinate and abscissa is x-coordinate.

Ordinate of T = -2

Abscissa of R = -2

(Ordinate of T) – (Abscissa of R) = -2 - (-2)

                                                     = -2 + 2

                                                     = 0

Therefore, the correct option is (c).

(v)

Abscissa of Q = -3

Ordinate of S = 1

(Abscissa of Q) – (Ordinate of S) = -3 - 1

                                                      = -4

Therefore, the correct option is (a).

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