Respuesta :

Answer:

2KI(aq) + BaS(aq) = BaI2 + K2S

Explanation:

Kl(aq) + BaS(aq)

Thus is a reaction between Potassium Iodide and Barium Sulfide

The product will be Barium Iodide and potassium Sulfide.

2KI(aq) + BaS(aq) = BaI2 + K2S