Answer:
The answer is below
Step-by-step explanation:
The question is not complete let us assume a mean of 80 and a standard deviation of 10.
The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
[tex]z=\frac{x-\mu}{\sigma} \\\\where\ \mu=mean, \sigma=standard\ deviation\\\\for\ a\ sample\ size(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} } \\\\[/tex]
Given that μ = 80, σ = 10
For x = 60:
[tex]z=\frac{x-\mu}{\sigma} =\frac{60-80}{10}=-2\\ \\\\\\[/tex]
For x = 100:
[tex]z=\frac{x-\mu}{\sigma}=\frac{100-80}{10}=2\\\\ \\\\[/tex]
Therefore from the normal distribution table, P(60 < x < 100) = P(-2 < z < 2) = P(z < 2) - P(z < -2) = 0.9772 - 0.0228 = 0.9544
