Answer:
a). [tex]-\frac{1}{2}[/tex]
b). x ≠ 1.5
Step-by-step explanation:
g(x) = (x - 3)(x - 3)
f(x) = -4x + 6
a). [tex](\frac{g}{f})(x)=\frac{(x-3)(x-3)}{-4x+6}[/tex]
[tex]=\frac{x^2-6x+9}{-4x+6}[/tex]
[tex](\frac{g}{f})(2)=\frac{2^2-6(2)+9}{-4(2)+6}[/tex]
[tex]=\frac{4-12+9}{-8+6}[/tex]
[tex]=\frac{1}{-2}[/tex]
[tex]=-\frac{1}{2}[/tex]
b). Function [tex](\frac{g}{f})(x)[/tex] is defined when denominator is equal to zero.
-4x + 6 ≠ 0
4x ≠ 6
x ≠ [tex]\frac{6}{4}[/tex]
x ≠ 1.5
