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In a tug-of-war game on one campus, 15 students pull on a rope at both ends in an effort to displace the central knot to one side or the other. Two students pull with force 51 N each to the right, four students pull with force 135 N each to the left, five students pull with force 136 N each to the left, three students pull with force 114 N each to the right, and one student pulls with force 188 N to the left. Assuming the positive direction to the right, how big is the net pull on the knot

Respuesta :

oladayoademosu

Answer:

964 N

Explanation:

If we assume the positive direction is right, we multiply each force by the number of students applying each force then sum it up. So,

2 × (+ 51 N) + 4 × (-135 N) + 5 × (-136 N) + 3 × (+ 114 N) + 1 × (-188 N)

= + 102 N -  540 N - 680 N + 342 N - 188 N

= + 444 N - 1408 N

= - 964 N

The net pull on the knot is 964 N

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