Answer:
Should he be surprised at this result
The found proportion is 1.56 standart deviations away from the expected. we should no be surprised .
Step-by-step explanation:
p=0,44
q=1-0.44=0.56
u=p=0,44
o=[tex]\sqrt{pq/n}[/tex]=[tex]\sqrt{(0.44)(0.56)/244}[/tex] = 0.032
proportion of students in binge drinking 96/244 = 0.39
The found proportion is 1.56 standart deviations away from the expected. we should no be surprised .
