Answer:
[tex]v=0m/s[/tex]
Explanation:
From the question we are told that
Mass of object[tex]M=10kg[/tex]
Amplitude[tex]A=0.10m[/tex]
SHM [tex]w=2.0 times per second.[/tex]
Distance from equilibrium [tex]0.10m[/tex]
Generally the equation for SHM displacement from equilibrium position is mathematically given by
[tex]v=Aw\sqrt{1-\frac{x^2}{A^2}}[/tex]
For [tex]x=0.10[/tex]
Therefore
[tex]v=Aw\sqrt{1-\frac{0.10^2}{A^2}}[/tex]
[tex]v=0.10*2\sqrt{1-\frac{0.10^2}{0.10^2}}[/tex]
[tex]v=0.10*2\sqrt{1-1}[/tex]
[tex]v=0m/s[/tex]
