Answer:
a = 14 m/min²
Step-by-step explanation:
The displacement of bike is given by :
[tex]s(t)=t^3-2t^2+3[/tex]
Velocity, [tex]v=\dfrac{ds(t)}{dt}[/tex]
Finding velocity of the bike.
[tex]v=\dfrac{d}{dt}(t^3-2t^2+3)\\\\=3t^2-4t[/tex]
Acceleration, [tex]a=\dfrac{dv(t)}{dt}[/tex]
[tex]a=\dfrac{d}{dt}(3t^2-4t)\\\\=6t-4[/tex]
At t = 3 minutes,
a = 6(3) - 4
= 18-4
= 14 m/min²
So, the bike's acceleration after 3 minutes is 14 m/min².
