contestada

If 0.42 mole of helium occupies 9.9 L, how
many moles must be added to inflate the
balloon to 17.0 L?

Respuesta :

Answer :

0.301 moles

Further explanation

Avogadro's hypothesis:  

In the same T,P and V, the gas contains the same number of molecules  

So the ratio of gas volume will be equal to the ratio of gas moles  

 

Given

n₁=initial mol of Helium : 0.42

V₁=initial volume : 9.9 L

V₂=final volume : 17 L

Required

number of moles added

Analysis

Use formula :

[tex]\tt \dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}[/tex]

Solution

[tex]\tt n_2=\dfrac{n_1\times V_2}{V_1}\\\\n_2=\dfrac{0.42\times 17}{9.9}\\\\n_2=0.721~moles[/tex]

moles added :

0.721 - 0.42 =0.301 moles

Paraphrase

0.301 moles must be added to inflate the  balloon to 17.0 L