Answer: the reliability will be worse
Explanation:
Suppose we used 0.5 M NaOH to titrate our vinegar sample instead of 0.1 M.
Now by using 0.5M instead of 0.1M we are increasing the concentration of NaOH,
We know that the moles used = Volume x concnetration.
so for the same no of moles, if the concentration increases, the volume decreases.
Hence it will consume less NaOH.
now Since the volume decreases, the titration volume of less number will increase the % error.
Therefore the reliability will be worse.
The effect that the concentration of the added base has on the reliability of the results of the titration in question is; The reliability will be worse.
We are told that;
0.5 M NaOH is to be used to titrate a vinegar sample instead of 0.1 M.
Now, 0.5 M means a concentration of 0.5 and since it is higher than 0.1M, it means the concentration of NaOH will increase.
Formula for number of moles used is;
n = V × M
Where;
n is number of moles
V is volume
M is concentration
We can see that number of moles is directly proportional to the volume and concentration.
Thus, if the number of moles remains unchanged, as we have increased the concentration, it means that the volume will decrease.
Thus, lesser volume of NaOH will be used and as a result of this decrease in volume, there will be a greater possibility of error.
In conclusion, we can say that the reliability will be worse.
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