Answer:
m = 6.4 kg
Explanation:
Now, we use the following equation to find the mass of the gel:
[tex]P = \rho gh[/tex]
where,
P = (60 mm of Hg)(133.3 Pa/1 mm of Hg) = 7999.2 Pa = 7.99 KPa
ρ = density of gel = [tex]\frac{m}{V} = \frac{m}{\pi r^2 h}[/tex]
m = mass of gel = ?
r = radius of cylindrical tank = 5 cm = 0.05 m
h = height of tank
Therefore,
[tex]7999.2 Pa = (\frac{m}{\pi(0.05\ m)^2\ h})(9.81\ m/s^2)h\\\\\frac{(7999.2\ Pa)(\pi)(0.05\ m)^2}{9.81\ m/s^2} = m\\[/tex]
m = 6.4 kg
