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10.0 mL of 0.0400 M KBrO3 and 10.0 mL 0.100 M HCl is mixed with 10.0 mL of 0.0100 M KI, 10.0 mL 0.00100 M Na2S2O3, 1.0 mL of starch solution, and 10.0 mL H2. What is the concentration of H in this mixture expressed as molarity?

Respuesta :

ajeigbeibraheem

Answer:

0.0196

Explanation:

The Total volume of the solution = Volume of [tex](KBrO_3 + HCl + KI +Na_2S_2O_3 + Starch + H_2O)[/tex]

= 10 mL + 10 mL + 10 mL+ 10 mL + 1 mL + 10 mL

= 51 mL

The concentration of  [tex][H^+] = \dfrac{ mL \ used \times 0.1 \ M}{total \ volume}[/tex]

[tex]= \dfrac{10 \ mL \times 0.1 M}{51 \ mL}[/tex]

= 0.0196

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