Answer:
20.39 g of O2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO3 —> 2KCl + 3O2
Next, we shall determine the mass of KClO3 that decomposed and the mass of O2 produced from the balanced equation. This is illustrated below:
Molar mass of KClO3 = 122.4 g/mol
Mass of KClO3 from the balanced equation = 2 × 122.4 = 244.8 g
Molar mass of O2 = 32 g/mol
Mass of O2 from the balanced equation = 3 × 32 = 96 g
Summary:
From the balanced equation above,
244.8 g of KClO3 decomposed to produce 96 g of O2.
Finally, we shall determine the mass of O2 produced from the decomposition of 52 g of KClO3. This can be obtained as follow:
From the balanced equation above,
244.8 g of KClO3 decomposed to produce 96 g of O2.
Therefore, 52 g of KClO3 will decompose to produce =
(52 × 96)/244.8 = 20.39 g of O2.
Thus, 20.39 g of O2 is produced.
