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What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (4, 1)?

y − 1 = −2(x − 4)
y – 1 = (x – 4)
y – 1 = (x – 4)
y − 1 = 2(x − 4)

What is the equation in pointslope form of the line that is parallel to the given line and passes through the point 4 1 y 1 2x 4 y 1 x 4 y 1 x 4 y 1 2x 4 class=

Respuesta :

gmany

Answer:

y - 1 = -2(x - 4)

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

Parallel lines have the same slope.

Calculate the slope of the given line.

Substitute the coordinetes of the poin from the graph

(-2, 1) and (-3, 3):

[tex]m=\dfrac{3-1}{-3-(-2)}=\dfrac{2}{-1}=-2[/tex]

Put the value of the slope and the coordinates of the point (4, 1) to the equation of a line:

[tex]y-1=-2(x-4)[/tex]

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