Respuesta :

Hagrid
The general form of the equation [tex] 5x^{2} -20x = 15 [/tex] is [tex] x^{2} -4x -3 =0 [/tex]. The general form of an equation is [tex]A x^{2} + Bx +C=0[/tex]

Dividing the whole equation by 5 and transferring 3 to the left side yields the answer [tex] x^{2} -4x-3 = 0[/tex]

Answer:

Option B is correct

[tex]x^2-4x-3 = 0[/tex]

Step-by-step explanation:

The general form of the equation is given by:

[tex]Ax^2+Bx+C = 0[/tex]

Given the equation:

[tex]5x^2-20x = 15[/tex]

⇒[tex]5(x^2-4x) = 15[/tex]

Divide both sides by 5 we have;

[tex]x^2-4x =3[/tex]

Subtract 3 from both sides we have;

[tex]x^2-4x-3 = 0[/tex]

Therefore, the general form of the equation is, [tex]x^2-4x-3 = 0[/tex]

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