Respuesta :
3 consecutive even integers : x, x + 2, x + 4
x + (x + 2) + (x + 4) = -84.....combine like terms
3x + 6 = - 84.......subtract 6 from each side
3x = -84 - 6
3x = - 90...divide both sides by 3
x = -90/3
x = -30
x + 2 = -30 + 2 = -28
x + 4 = -30 + 4 = -26
so ur 3 numbers are : -26, -28, -30
x + (x + 2) + (x + 4) = -84.....combine like terms
3x + 6 = - 84.......subtract 6 from each side
3x = -84 - 6
3x = - 90...divide both sides by 3
x = -90/3
x = -30
x + 2 = -30 + 2 = -28
x + 4 = -30 + 4 = -26
so ur 3 numbers are : -26, -28, -30
Since they are consecutive even integers, they would differ by 2.
Let the first even integer be x.
x , x + 2, x + 4
Sum = -84
x + x + 2 + x + 4 = -84
x + x + x + 2 + 4 = -84
3x + 6 = -84
3x = -84 - 6
3x = -90
x = -90/3
x = -30
Hence the even integers are: x, x + 2 , x + 4
-30, -30 + 2, -30 + 2 + 2
-30, -28, -26
Hence the consecutive even integers are: -30, -28, -26
Let the first even integer be x.
x , x + 2, x + 4
Sum = -84
x + x + 2 + x + 4 = -84
x + x + x + 2 + 4 = -84
3x + 6 = -84
3x = -84 - 6
3x = -90
x = -90/3
x = -30
Hence the even integers are: x, x + 2 , x + 4
-30, -30 + 2, -30 + 2 + 2
-30, -28, -26
Hence the consecutive even integers are: -30, -28, -26