Respuesta :
Recall that:
sin(A + B) = sinAcosB + cosAsinB
Therefore:
sin11°cos19° + cos11°sin19° = sin(11° + 19°)
= sin30° = 0.5
I hope this explains it.
sin(A + B) = sinAcosB + cosAsinB
Therefore:
sin11°cos19° + cos11°sin19° = sin(11° + 19°)
= sin30° = 0.5
I hope this explains it.
The value of sin(11°)cos(19°) + cos(11°)sin(19°) is; 0.5
From trigonometric identities, we know that;
sin (A + B) = sinAcosB + cosAsinB
Now we are given the equation;
sin(11°)cos(19°) + cos(11°)sin(19°)
Comparing it with the trigonometric identity written above, we can say that;
sin (11° + 19°) = sin(11°)cos(19°) + cos(11°)sin(19°)
Thus; sin (11° + 19°) = sin 30° = 0.5
In conclusion, we can say that sin(11°)cos(19°) + cos(11°)sin(19°) is equal to 0.5.
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