Respuesta :

Recall that:

sin(A + B) = sinAcosB + cosAsinB

Therefore:

sin11°cos19° + cos11°sin19° = sin(11° + 19°)

                                                   = sin30° = 0.5            

I hope this explains it.

The value of sin(11°)cos(19°) + cos(11°)sin(19°) is; 0.5

From trigonometric identities, we know that;

sin (A + B) = sinAcosB + cosAsinB

Now we are given the equation;

sin(11°)cos(19°) + cos(11°)sin(19°)

Comparing it with the trigonometric identity written above, we can say that;

sin (11° + 19°) = sin(11°)cos(19°) + cos(11°)sin(19°)

Thus; sin (11° + 19°) = sin 30° = 0.5

In conclusion, we can say that sin(11°)cos(19°) + cos(11°)sin(19°) is equal to 0.5.

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