Respuesta :
If you put them together, +2.5y and -2.5y neutralize themselves while 5x and 3x become 8x.
2.5y + 3x = 27
5x – 2.5y = 5
8x = 32
x = 4
2.5y + 3x4 = 27
2.5y + 12 = 27
2.5y = 27-12
2.5y = 15
y = 15/2.5
y = 6
X = 4
Y = 6
Answer:
The result of adding the two equations is:
[tex]8x=32[/tex]
And the solution to the system is (4, 6).
Step-by-step explanation:
We are given the system of equations:
[tex]\left\{ \begin{array} \ 2.5y+3x=27 \\ 5x-2.5y=5 \end{array}[/tex]
We can solve by elimination. If we add the two equations together, we acquire:
[tex](2.5y+3x)+(5x-2.5y)=(27+5)[/tex]
Simplifying yields:
[tex](2.5y-2.5y)+(3x+5x)=(32)[/tex]
Combine like terms. Therefore, we the two equations are added together, we obtain:
[tex]8x=32[/tex]
Solve for x by dividing both sides by 8:
[tex]x=4[/tex]
With the value of x, we can solve for y. Using the first equation:
[tex]2.5y+3x=27[/tex]
Substitute 4 for x and solve for y:
[tex]\displaystyle \begin{aligned} 2.5y + 3(4) & = 27 \\ \\ 2.5y + 12 & = 27 \\ \\ 2.5y & = 15 \\ \\ y & = 6 \end{aligned}[/tex]
In conclusion, our solution to the system is (4, 6).