Answer:
8/73
0.10959
21 players
Step-by-step explanation:
Given that:
Number of teams = 25
Number of players per team = 73
Number of players chosen for drug testing = 8
A) What is the probability that Erik Red is chosen for random drug testing in a specified week of the foosball season?
Number chosen per team / number of players per team
8 / 73 = 0.10959
B) What is the probability that Erik Red is chosen for random drug testing at least 5 times in the first 9 weeks of the foosball season?
P( being chosen at least 5 times)
USing binomial. Distribution
P(X =x) = nCr * p^x * (1-p)^n-x
To save computation time, we can use the binomial distribution calculator :
P(x≥5):p(x = 5) + p(x = 6) + p(x =7) + p(x = 8) +. P(x = 9) = 0.00136
C) What is the expected number of players who are chosen for random drug testing at least 4 times in the first 9 weeks of the foosball season?
Number who are chosen atleast 4 times :
P(x ≥ 4) = p(x = 4) + p(x = 5) + p(x = 6) + p(x = 7) + p(x = 8) +. P(x =9) = 0.0115
P(x ≥ 4) * number of players per team * nunber of teams in league
0.0115 * 73 * 25 = 20.9875
= 21 players
D) Let Y be the number of players who are chosen for random drug testing at least 4 times in the first 9 weeks of the foosball season. What is the maximum possible value of Y, i.e., the largest k such that P(Y=k) > 0?
