Given :
Distance of bird from sea level, [tex]d_1 = 3\dfrac{5}{8} = \dfrac{29}{8}\ feet[/tex] .
Distance between fish and sea level, [tex]d_2=5\dfrac{1}{3}=\dfrac{16}{3}\ feet[/tex] .
To Find :
Distance between bird and fish.
Solution :
Distance between bird and fish is given by :
[tex]D=d_1+d_2\\\\D = \dfrac{29}{8}+\dfrac{16}{3}\\\\D=8.958\ feet[/tex]
Therefore, distance between bird and fish is 8.958 feet.
Hence, this is the required solution.
