Two cars, initially 12 meters apart, zip towards one another at the speeds shown. At what point will the collision occur? Explain how you arrived at your answer. Car A: 1.4m/s car B: 2.2m/s

Answer:
s₁ = 4.67 m from car A
Explanation:
Since, the cars are moving at a constant speed. Hence, we will apply the equation for uniform motion here:
s = vt
where,
s = distance covered
v = velocity
t = time taken
For Car A:
s₁ = (1.4 m/s)t
For Car B:
s₂ = (2.2 m/s)t
Because the time will be same at the collision. At collision the distance covered by Car A and Car B must be 12 m altogether. Hence:
s₁ + s₂ = 12 m
using values:
(1.4 m/s)t + (2.2 m/s)t = 12 m
t = 12 m/3.6 m/s
t = 3.333 s
Substitute this in the equation of s₁:
s₁ = (1.4 m/s)(3.33 s)
s₁ = 4.67 m from car A