Respuesta :
Answer:
b
Explanation:
The correct answer would be 45.
Assuming that the 10 soils are each represented by A, B, C, D, E, F, G, H, I, J.
A can combine with 9 others as: AB AC AD AE A F AG AH AI AJ
B can combine as: BC BD BE BF BG BH BI BJ
C as: CD CE CF CG CH CI CJ
D as: DE DF DG DH DI DJ
E as: EF EG EH EI EJ
F as: FG FH FI FJ
G as: GH GI GJ
H as: HI HJ
I as: IJ
Adding all the combinations together = 45
In other words;
[tex]^{10}C_2[/tex] = [tex]\frac{10!}{(2!(10 - 2)!)}[/tex] = 45
The soil mixtures must the scientist create in order to test all possible combinations of the 10 soil types- b. 45.
Given
soil samples = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
each mixture must have two sample
Solution
- We have to mix 2 soils in equal amounts. Then, the total number of possible soil mixtures are:-
- 1 and 2, 1 and 3, 1 and 4, 1 and 5, 1 and 6, 1 and 7, 1 and 8, 1 and 9, 1 and 10 = >9
- 2 and 3, 2 and 4, 2 and 5, 2 and 6, 2 and 7, 2 and 8, 2 and 9, 2 and 10 => 8
- 3 and 4, 3 and 5, 3 and 6, 3 and 7, 3 and 8, 3 and 9, 3 and 10 => 7
- 4 and 5, 4 and 6, 4 and 7, 4 and 8, 4 and 9, 4 and 10 => 6
- 5 and 6, 5 and 7, 5 and 8, 5 and 9, 5 and 10 => 5
- 6 and 7, 6 and 8, 6 and 9, 6 and 10 => 4
- 7 and 8, 7and 9, 7 and 10 => 3
- 8 and 9, 8 and 10 => 2
- 9 and 10 => 1
Then Total mixtures possible are =
9 + 8 + 7 + 6+ 5 + 4 + 3 + 2 + 1
= 45
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