Answer:
The answer is "0.0045 Wb"
Explanation:
Using formula:
[tex]\to E_A= \sqrt{2} \pi N_c f \phi\\\\\to \phi = \frac{E_A}{\sqrt{2} \pi N_c f}\\\\[/tex] .......(a)
Calculating the phase voltage of the machine:
[tex]V_\phi = \frac{V_L}{\sqrt{3}}[/tex]
[tex]= \frac{4.16 \times 10^3}{\sqrt{3}}\\\\=2401.7[/tex]
Substitute the value from equation (a):
[tex]\phi= \frac{2401}{\sqrt{2} \times \pi \times 2000 \times 60}[/tex]
[tex]=4.503 \times 10^{-3}\\\\= 0.0045 \ wb[/tex]
The rotor flux = 0.0045 Wb
