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Consider the equation 3a+0.1n=123. If we solve this equation for n, which equation would result? A. 0.1n=123-3a B. N=123-3a-0.1 C.N=1,230-30a D. 3a-123 over 0.1 =n

Respuesta :

adioabiola

Answer:

n = (123 - 3a) / 0.1

Step-by-step explanation:

Given:

3a + 0.1n = 123

Solve for n

3a + 0.1n = 123

Subtract 3a from both sides

3a + 0.1n - 3a = 123 - 3a

0.1n = 123 - 3a

Divide both sides by 0.1

n = (123 - 3a) / 0.1

The resulting equation if 3a + 0.1n = 123 is solved for n is n = (123 - 3a) / 0.1