Respuesta :
Answer:
y=-3x+5
bring (4,-7) in other three lines
you will know that it is unreasonable that
-7=-14
-7=-17
-7=14
The equation for the line perpendicular to the line represented by the equation [tex]y= \ \frac{1}{3} x-2[/tex] that passes through the point [tex](4,-7)[/tex] will be [tex]y=-3x+5[/tex].
What is equation for the perpendicular line ?
Equation for the perpendicular line, the perpendicular lines have opposite-reciprocal slopes.
Now,
The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.
Equation of a perpendicular line [tex]y=mx-b[/tex]
Here, [tex]m=[/tex] slope
So,
We have
[tex]y= \ \frac{1}{3} x-2[/tex]
Here,
[tex]m = \frac{1}{3}[/tex]
As mentioned above, we have to find the slope of perpendicular,
i.e.
(slope of perpendicular) [tex]m[/tex] [tex]=-3[/tex]
So,
[tex]y=mx-2[/tex]
[tex]y=(-3)x-b[/tex]
We have
Point [tex](4,-7)[/tex] through which line passes. i.e.
[tex]x=4[/tex]
[tex]y=(-7)[/tex]
Therefore,
[tex]-7=(-3)*4-b[/tex]
⇒ [tex]b=7-12[/tex]
[tex]b=(-5)[/tex]
So, Equation of a perpendicular line,
[tex]y=-3x+5[/tex]
So, Equation of a perpendicular line, [tex]y=-3x+5[/tex] which is derived from [tex]y=mx-b[/tex] .
Hence, we can say that the equation for the line perpendicular to the line represented by the equation [tex]y= \ \frac{1}{3} x-2[/tex] that passes through the point [tex](4,-7)[/tex] will be [tex]y=-3x+5[/tex].
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