The marine-life store would like to set up fish tanks that contains the equal amounts of angle fish, swordtails, and guppies. What is the greatest number of tanks that can be set up if the store has12angle fish, 24 swordtails, and 30 guppies

Respuesta :

so find the greatest common factor

12=2*2*3
24=2*2*2*3
30=2*3*5
common factors is 2*3 which is 6

6 tanks

12/6=2
24/6=4
30/6=5

6 tanks is answer

To find the greatest number of tanks that can be set up if the store has 12 angle fish, 24 swordtails, and 30 guppies

We will find GCD(Greatest Common Divisor) of 12, 24 and 30.

12=2×2×3

24=2×2×2×3

30=2×3×5

GCD(12,24,30)

=2×3

=6

Which is ,Greatest Number of tanks  that contains the equal amounts of angle fish, swordtails, and guppies.