contestada

Complete combustion of 5.90 g of a hydrocarbon produced 19.2 g of CO2 and 5.89 g of H2O. What is the empirical formula for the hydrocarbon?

Respuesta :

Yipes
[tex]44g \ \ CO_{2} \ \ \ \rightarrow \ \ \ 12g \ C\\ 19,2g \ CO_{2} \ \ \rightarrow \ \ \ x\\\\ x=\frac{19,5g*12g}{44g}\approx5,32g \ \ \ \ \Rightarrow n=\frac{5,32g}{12\frac{g}{mol}}\approx0,44mol\\\\\\ 18g \ H_{2}O \ \ \ \rightarrow \ \ \ 2g \ H\\ 5,89g \ \ \ \ \ \ \ \rightarrow \ \ \ y\\\\ y=\frac{5,89g*2g}{18g}=0,65g \ \ \ \ \Rightarrow \ n=\frac{0,65g}{1\frac{g}{mol}}=0,65mol\\\\ n_{C}:n_{H}=0,44:0,65\approx1:1\\\\ CH \ - \ empirical \ formula[/tex]