Respuesta :

Yipes
[tex]M_{KPH}=39,1+30,97+1,01=71,08\frac{g}{mol}\\\\ but \ if \ you \ asking \ for \ Potassium \ hydrogen \ phthalate\\\\ M_{C_{8}H_{5}KO_{4}}=12,01*8+1,01*5+39,1+16*4=204,23\frac{g}{mol}[/tex]