[tex]m=0,2m*(\frac{1}{2})^{\frac{t}{14,3}} \ \ | \:0,2m\\\\
\frac{m}{0,2m}=(\frac{1}{2})^{\frac{t}{14,3}}\\\\
5=(\frac{1}{2})^{\frac{t}{14,3}} \\\\
log_{a}b=c \ \ \Leftrightarrow \ \ a^{c}=b\\\\
\frac{t}{14,3}=log_\frac{1}{2}5\\\\
\frac{t}{14,3}=2,31 \ \ |*14,3\\\\
t = 33,033\approx 33days [/tex]
