The molality of ammonia is 20.392 mol/kg.
What is Molality?
- Molality (m) or molal concentration, is the amount of a substance dissolved in a certain mass of solvent.
- It is defined as the moles of a solute per kilograms of a solvent.
- The units of molality are m or mol/kg.
How to calculate molality?
Molality(m) = moles of solute / kilograms of solvent
m = mol / kg
26% of solution of ammonia means 26g of ammonia is present in 100g of solution or 75g of water.
Molality(m) = Number of moles of solute(NH3) / Total mass of solvent
Molar mass of NH₃ = Atomic mass of N + Atomic mass of H x 3
= 14 + 1 x 3
= 17g/mol
No. of moles of NH₃ = Actual mass / molar mass
= 26g / 17g/mol
= 1.5294 mol
Total mass of solvent (water) = 75g = 0.075kg
Molality = no. of moles of NH₃ / Total mass of solvent
= 1.5294mol / 0.075kg
= 20.392 mol/kg.
Hence, the molality of ammonia is 20.392 mol/kg.
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