The value of "f" will be "14".
According to the question,
By solving the brackets, we get
→ [tex]\frac{1}{2}f-\frac{6}{2} =4[/tex]
By taking L.C.M, we get
→ [tex]\frac{f-6}{2} =4[/tex]
By applying cross-multiplication, we get
→ [tex]f -6=8[/tex]
By adding "6" both sides, we get
→ [tex]f-6+6=8+6[/tex]
→ [tex]f =14[/tex]
Thus the above answer is right.
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