If a penny is dropped from a building that is 95 m tall then it would 3.111 seconds take the penny to hit the ground below
What are the three equations of motion?
There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
Keep in mind that these calculations only apply to uniform acceleration.
As given in the problem, A penny is dropped from a building that is 95 m tall,the initial velocity of the penny is zero, the acceleration acting is due to the acceleration due to gravity
height of the building (S) = 95 meters
initial velocity(u) = 0 m/s
acceleration(a) = 9.81 m/s²
By using the second equation of motion given by newton
S = ut + 1/2at²
S = 95 m ,u= 0 m/s , a= 9.81 m/s² and t =? seconds
95 = 0 + 9.81t²
t² = 95/9.81
t = 3.111 seconds
Thus, if a penny is dropped from a building that is 95 m tall then it would take 3.111 seconds for the penny to hit the ground below
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