Which expression is equivalent to (8^2)^-4

Answer:
C: [tex]\frac{1}{8*8*8*8*8*8*8*8}[/tex]
Step-by-step explanation:
[tex]a^{-n} = \frac{1}{a^n}[/tex]
Since a = [tex]8^2[/tex] :
[tex](8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}[/tex]
Since n = 4 :
[tex](8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}[/tex]