Answer:
[tex]M_{CuCl_2}=134.44g/mol\\\\M_{CuCl_2\ H_2O}=152.44g/mol\\\\M_{CuCl_2\ 2H_2O}=170.44g/mol[/tex]
Explanation:
Hello,
In this case, since anhydrous copper (II) chloride is CuCl₂ whose molar mass is:
[tex]M_{CuCl_2}=m_{Cu}+m_{Cl}*2=63.54+35.45*2=134.44g/mol[/tex]
We can also find copper (II) chloride both monohydrate and dihydrate as CuCl₂·H₂O and CuCl₂·2H₂O respectively, whose molar masses are:
[tex]M_{CuCl_2\ H_2O}=m_{Cu}+m_{Cl}*2+m_{H_2O}=63.54+35.45*2+18=152.44g/mol\\\\M_{CuCl_2\ 2H_2O}=m_{Cu}+m_{Cl}*2+m_{H_2O}*2=63.54+35.45*2+18*2=170.44g/mol[/tex]
Best regards.
