Given:
[tex]3x + 4y = 36\\\\y = \frac{1}{2}x+8[/tex]
To find:
x and y=?
Solution:
[tex]3x + 4y = 36.....................(a)\\\\y = \frac{1}{2}x+8.................(b)[/tex]
In equation (b) multiply by 4 and then add by equation (a):
[tex]4y = \frac{4}{2}x+ 32\\\\ \to 2x-4y=-32[/tex]
[tex]\to 3x + 4y = 36[/tex]
[tex]+ \ \ \ +\ \ \ +\\\\\to 5x= 4\\\\\to x=\frac{4}{5}\\\\[/tex]
Putting the value of x into the equation (b):
[tex]\to y = \frac{1}{2} \times \frac{4}{5}+8\\\\\to y = \frac{2}{5}+8\\\\\to y = \frac{2+40}{5}\\\\\to y = \frac{42}{5}\\\\[/tex]
Therefore, the final answer is "[tex]\frac{4}{5}\ \ and\ \ \frac{42}{5}[/tex]".
Learn more:
brainly.com/question/1632711
