contestada

There are 40 liters of helium in a balloon at 100 K. If the temperature of
the balloon is increased to 200 K, what will the new volume of the balloon
be?

Respuesta :

Explanation:

By the Ideal Gas Law, PV = nRT.

Assuming that the pressure inside the balloon remains the same, that means volume is directly proportional to temperature.

40 litres at 100K

=> 80 litres at 200K.

The new volume of the balloon will be "80 L".

Helium gas:

Research balloons, as well as compressed gasses balloons, are all filled with helium gas. Is therefore employed as such an inert barrier for arc welding, to pressurize liquid-fueled rockets storage tanks, as well as throughout the tunnels.

According to the question,

Temperature, T₁ = 100 K

                       T₂ = 200 K

Volume, V₁ = 40 L

              V₂ = ?  

We know the relation,

→ [tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

or,

New volume, V₂ = [tex]\frac{V_1\times T_2}{T_1}[/tex]

By substituting the values,

                           = [tex]\frac{40\times 200}{100}[/tex]

                           = [tex]\frac{8000}{100}[/tex]

                           = 80 L

Thus the above response is correct.

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