Answer:
[tex]\frac{14d^{3}}{3b^{2}}[/tex]
Step-by-step explanation:
[tex]\frac{10ab}{c^{3}d}[/tex] ÷ [tex]\frac{15ab^{3}}{7c^{3}d^{4}}[/tex] = [tex]\frac{10ab}{c^{3}d}*\frac{7c^{3}d^{4}}{15ab^{3}}\\[/tex]
[tex]=\frac{2ab}{c^{3}d}*\frac{7c^{3}d^{4}}{3ab^{3}}\\\\=\frac{2*7*a^{1-1}*c^{3-3}*d^{4-1}}{3b^{3-1}}\\\\=\frac{14a^{0}*c^{0}*d^{3}}{3b^{2}}\\\\=\frac{14*1*1*d^{3}}{3b^{2}}\\\\=\frac{14d^{3}}{3b^{2}}[/tex]
Hint:
[tex]\frac{x^{m}}x^{n}=x^{m-n}; m>n\\\\\\\frac{x^m}{x^{n}}=\frac{1}{x^{n-m}},n>m\\\\x^{0} =1[/tex]
