Answer:
[tex]b=15.6[/tex]
Step-by-step explanation:
[tex]4\frac{1}{3}*b+b=6b-10.4[/tex]
Convert the fraction to an improper fraction ([tex]a\frac{b}{c}= \frac{ac+b}{c}[/tex]):
[tex]\frac{13}{3} *b+b=6b-10.4[/tex]
Simplify multiplication:
[tex]\frac{13b}{3}+b=6b-10.4[/tex]
Now simplify addition ([tex]x=1x[/tex]):
[tex]\frac{13b}{3}+1b\\\\\frac{13b}{3}+\frac{1b}{1}\\\\\frac{13b}{3}+\frac{3b}{3} \\\\\frac{16b}{3}=6b-10.4[/tex]
Undo the fraction by multiplying both sides by 3:
[tex]3(\frac{16b}{3})=3(6b-10.4)\\\\16b=18b-31.2[/tex]
Subtract 18b from both sides:
[tex]16b-18b=18b-18b-31.2\\\\-2b=-31.2[/tex]
Divide both sides by -2 to isolate the variable b:
[tex]\frac{-2b}{-2}=\frac{-31.2}{-2} \\\\b=15.6[/tex]
The value of b is 15.6.
:Done
