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At entrance to the nozzle, the pressure is 0.180 MPa and the temperature is 1200 K. The kinetic energy of the gas entering the nozzle is very much smaller than ... The specific heat of the exhaust gas varies with temperature approximately as follows: ... Problem 4P: In an aircraft jet engine at takeoff, the combustion product.
In this exercise we want to calculate the temperature for each value informed in the text from the given equation, so we have to:
A)[tex]Cp = 0.959+ \frac{31910.95}{250000} [/tex]
B)[tex]Cp = 0.959+ \frac{29010.95}{250000} [/tex]
C)[tex]Cp = 0.959+ \frac{26110.95}{250000} [/tex]
Then given the equation as:
[tex]Cp = 0.959 + 1.16 * 10^{-4}T + 3.65 * 10^{-8}T_2 [/tex]
Replacing the value of T with the first value informed in the text we have:
A) 1100, will be:
[tex]Cp = 0.959 + 1.16 * 10^{-4}(1100) + 3.65 * 10^{-8}(1200)\\ Cp = 0.959+ \frac{31910.95}{250000} [/tex]
B) 1000, will be:
[tex]Cp = 0.959 + 1.16 * 10^{-4}(1000) + 3.65 * 10^{-8}(1200)\\Cp = 0.959+ \frac{29010.95}{250000} [/tex]
C) 900, will be:
[tex]Cp = 0.959 + 1.16 * 10^{-4}(900) + 3.65 * 10^{-8}(1200)\\Cp = 0.959+ \frac{26110.95}{250000} [/tex]
See more about temperature at brainly.com/question/7510619