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You are painting a panel with a diamond-shaped window, as shown. You have to put up tape around the edge of the window to keep the paint off. Find the length of tape you need to nearest inch

You are painting a panel with a diamondshaped window as shown You have to put up tape around the edge of the window to keep the paint off Find the length of tap class=

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Answer:

Length of tape required = 10 inches

Step-by-step explanation:

Length of the tape around the edge of the window = perimeter of the window

Since, distance between two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

d = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

For the side having extreme ends as (15, 18) and (21, 10),

[tex]d_1=\sqrt{(18-10)^2+(15-21)^2}[/tex]

    [tex]=\sqrt{8^2+6^2}[/tex]

    = 10 inches

Side with extreme ends (21, 10) and (15, 2),

[tex]d_2=\sqrt{(21-15)^2+(10-2)^2}[/tex]

    [tex]=\sqrt{6^2+8^2}[/tex]

    [tex]=\sqrt{100}[/tex]

    = 10 inches

Distance between (15, 2) and (9, 10),

[tex]d_3=\sqrt{(15-9)^2+(2-10)^2}[/tex]

   [tex]=\sqrt{(6)^2+(-8)^2}[/tex]

   = 10 inches

Distance between (9, 10) and (15, 18),

[tex]d_4=\sqrt{(9-15)^2+(10-18)^2}[/tex]

    [tex]=\sqrt{(-6)^2+(-8)^2}[/tex]

    = 10 inches

Therefore, perimeter of the window = [tex]d_1+d_2+d_3+d_4[/tex]

                                                            = 10 + 10 + 10 + 10

                                                            = 40 inches

Length of tape required = 10 inches